15.2 days is 4 HALF LIVES. A bit over 6 ⋅ g of 222Rn will remain.The radioisotope radon-222 has a half-life of 3.8 days.The radioisotope radon-222 has a half-life of 3.8 days. How much of an initial 20.0 g sample of radon-222 would remain after 15.2 days?After 3 days a sample of radon-222 decayed to 58% of its original amount.The radioisotope radon-222 has a half life of 3.8 days. How much of a 73.9 g sample of radon-222 would be left after approximately 23 days? NotSoSmart May 25, 2018
Solved: The radioisotope radon-222 has a half-life of 3.8
The radioisotope radon-222 has a half life of 3.8 days. How much of a 73.9 g sample of radon-222 would be left after approximately 23 days? 1.2 g If an isotope decays the process of beta emissionRadon (/ ˈ r eɪ d ɒ n /) is a radioactive, colorless, odorless, tasteless noble gas, occurring naturally as the decay product of radium. It is one of the densest substances that remains a gas under normal conditions, and is considered to be a health hazard due to its radioactivity. Its most stable isotope, 222 Rn, has a half-life of 3.8 daysProblem 20 Medium Difficulty. After 3 days a sample of radon-222 has decayed to 58% of its original amount. (a) What is the half-life of radon-222? (b) How long will it take the sample to decay to 20% of its original amount?Rn-222 has a short half-life (3.8 days) and decays into a series of solid particulate products, known as radon progeny or radon daughters, all of which have even shorter half-lives (∼30 min or less).
Half-Life of Radon-222 Question? | Yahoo Answers
Find an answer to your question the radioisotope radon-222 has a half-life of 3.8 days. How much of a 73.9-gram sample of radon-222 would be left after approxim…Answer to: The radioisotope radon-222 has a half-life of 3.8 days. How much of a 65 g sample of radon-222 would be left after approximately 15...31. After 252 days a 12.0g starting sample of Scandium-42 contains only 1.5g of the isotope. What is the half life of scandium? (Points: 1) 32. The radioisotope radon-222 has a half life of 3.8 days. How much of a 10.g sample of radon-222 would be left after 15.2 days? (Points: 1)the radioisotope radon-222 has a half-life of 3.8 days; the radioisotope radon-222 has a half-life of 3.8 days. how much of a 73.9-g sample of radon-222 would be left after approximately 23 days? the radioisotope radon-222 has a half life of 3.8 days. how much of a 73.9the radioisotope radon-222 has a half-life of 3.8 days. How much of an initial 20.0g sample of radon-222 would remain after 15.2 days please solve using half-life or intergade law.
Half existence of radon-222 (t1/2)= 3.8 days
Time elapsed=15.2 days
Therefore, no. of part lives elapsed (n) = 15.2/3.8=4
Let the preliminary no. of atoms in the sample of Rn-222 be N0
Since the number of atoms provide to begin with is proportional to the mass of the initial pattern, N0= 20g
Therefore, quantity of the pattern left after 15.2 days, i.e 4 part lives= (1/2)^4×N0 = 1.25 g
Thus, 1.25 g of the preliminary sample of Rn-222 can be left after 15.2 days, as a result of radioactive decay.
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